L’Hospital’s_Rule
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Definition
Assume $f$ and $g$ are differentiable on $(a,b)$ and that $g'(x) \neq 0$ for all $x \in (a,b)$. If
$$ \lim_{x \to a^+} f(x) = 0 \quad\text{and}\quad \lim_{x \to a^+} g(x) = 0 $$then
$$ \lim_{x \to a^+} \frac{f(x)}{g(x)} = \lim_{x \to a^+} \frac{f'(x)}{g'(x)} $$provided the limit on the right-hand side exists.
The rule also applies to the indeterminate form $\frac{\infty}{\infty}$.
Proof
By the Generalized_Mean_Value_Theorem, for each $x \in (a,b)$ there exists $c_x$ between $a$ and $x$ such that
$$ \frac{f(x)}{g(x)} = \frac{f(x) - f(a)}{g(x) - g(a)} = \frac{f'(c_x)}{g'(c_x)} $$(using $f(a) = g(a) = 0$ by continuity).
As $x \to a^+$, we have $c_x \to a^+$, so the result follows.